find the constant k so that the planes x-2y+kz=0 and 2x+5y-z=0 are at the right angles
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given planes are at right angle if k = -8
Step-by-step explanation:
x - 2y + kz = 0
2x + 5y - z=0
Cos θ = | 1 * 2 + (-2)*5 + k(-1) / (√( 1² + (-2)² + k² * √2² + 5² +(-1)²)
Angle between these planes would be 90°
=> θ = 90°
=> Cos 90° = 0
=> 0 =| 1 * 2 + (-2)*5 + k(-1) / (√( 1² + (-2)² + k² * √2² + 5² +(-1)²)
=> 1 * 2 + (-2) * 5 + k(-1) = 0
=> 2 - 10 - k = 0
=> - 8 - k = 0
=> k = - 8
given planes are at right angle if k = -8
Learn more:
Angles between plane 3x-4y+5z =0 and 2x-y-2z=5 - Brainly.in
https://brainly.in/question/1713850
the acute angle between the two planes x+y+2z=3 and 3x-2y+2z=7 is.
https://brainly.in/question/8521781
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0
Answer:
I don't know
Step-by-step explanation:
I don't know but please mark me as brainlist
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