Question

find the constant term in the expansion of (x^2-1/x^2)^15 is​

Answer 1

The constant term is 1

Step-by-step explanation:

The equation is  $(x^{2} -\frac{1}{x^{2} } )^ {15}$

The given equation is equal to zero

$(x^{2} -\frac{1}{x^{2} } )^ {15}=0$

$(\frac{(x^{4} -1)}{x^{2} } )^ {15}=0$

$(\frac{(x^{4+15} -1^{15} )}{x^{2+15} } )=0$

$\frac{(x^{19} -1 )}{x^{17} } =0$

$x^{19}-1=0$

$x^{19}=1$

Here ,the constant term is 1