Question

find the constnt term in the polynomial(y-2)(y+3)

Answer 1

Answer:

The required constant term is "-6"

Step-by-step explanation:

To find the constant term in the polynomial (y - 2) (y + 3) ; first multiply it.

➙ (y - 2) (y + 3)

➙ y (y + 3) - 2(y + 3)

➙ y(y) + y(3) - 2(y) - 2(3)

➙ y² + 3y - 2y - 6

➙ y² + y - 6

For the polynomial ax² + bx + c ,

• ax² is called quadratic term
• bx is called linear term
• c is the constant term

By comparing y² + y - 6 with ax² + bx + c ; we get

a = 1

b = 1

c = -6

Therefore, -6 is the constant term of the given polynomial.

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Know more :

• ax² + bx + c is the general form of the quadratic polynomial.

        $\underline{\boxed{\sf x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a} }}$     is the quadratic formula.

• Nature of roots is determined by the value of the discriminant.

 ⇒ D = b² - 4ac

 If D > 0 ; the roots are real and unequal

 If D = 0 ; the roots are real and equal

 If D < 0 ; the roots are not real i.e., complex roots

Answer 2

$\huge\sf\underline{Solution}$

First We have to know constant term means it should be in form of Quadratic polynomial.So,multiply both

(y - 2) ( y + 3 )

y( y + 3) -2 ( y + 3)

y² + 3y -2y -6

y² + y -6 is the required polynomial

In ax² + bx + c

a is called as coefficient of x²

b is called as coefficient of x

c is called constant terms

Similary in Quadratic polynomial y² + y -6

1 is coefficient of y² term

1 is coefficient of y term

- 6 is called constant term

So,Required answer is -6