Question

Find the continued product of (n − 1)(n + 1)(n^2 + 1) with a attachment fast​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

$\mathrm{Expand}\:\left(n-1\right)\left(n+1\right)\left(n^2+1\right):\quad n^4-1$

$\mathrm{Expand}\:\left(n-1\right)\left(n+1\right):\quad n^2-1$

$=\left(n^2-1\right)\left(n^2+1\right)$

$\mathrm{Expand}\:\left(n^2-1\right)\left(n^2+1\right):\quad n^4-1$

$=n^4-1$