Math, asked by priya146, 1 year ago

find the coordinate equation A, where AB is the diameter of a circle whose Centre is (2,-3) and B is (1,4)

Kittiboo240: I was thinking I'm gonna fail if such q r gonna come...all the best guy!!!!

Nikitaparihar: biiii

priya146: thanks and same to you

adityakjha24: how one can fail by not knowing one question..

adityakjha24: btw.. all the best for ur exams..

Kittiboo240: its a joke

Kittiboo240: Thanks BTW

adityakjha24: :)

Nikitaparihar: thank you

adityakjha24: wlcm

Answers

Answered by adityakjha24

Formula = (y-y1)/ (x- x1) = (y2-y1)/(x2-x1)

x1 = 2 , x2 = 1

y1 = -3 ,y2 =4

by putting values in formula,

[y-(-3)]/(x-2) = [4-(-3)]/ (1-2)

(y+3)/(x-2) = 7/-1 = -7 /1

(y+3) = -7 (x-2)

y + 3 = -7x + 14

7x + y = 11

Hope it helps

Answered by Kittiboo240

U mean coordinates of point a?
Here is the answer...

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