find the coordinate equation A, where AB is the diameter of a circle whose Centre is (2,-3) and B is (1,4)
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Answered by
4
Formula = (y-y1)/ (x- x1) = (y2-y1)/(x2-x1)
x1 = 2 , x2 = 1
y1 = -3 ,y2 =4
by putting values in formula,
[y-(-3)]/(x-2) = [4-(-3)]/ (1-2)
(y+3)/(x-2) = 7/-1 = -7 /1
(y+3) = -7 (x-2)
y + 3 = -7x + 14
7x + y = 11
Hope it helps
x1 = 2 , x2 = 1
y1 = -3 ,y2 =4
by putting values in formula,
[y-(-3)]/(x-2) = [4-(-3)]/ (1-2)
(y+3)/(x-2) = 7/-1 = -7 /1
(y+3) = -7 (x-2)
y + 3 = -7x + 14
7x + y = 11
Hope it helps
Answered by
2
U mean coordinates of point a?
Here is the answer...
Here is the answer...
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