Find the coordinate of a point a where AB is the diameter of a circle whose center is the
2,-3 and B is 1,4
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Answer:
A(3,-10)
Step-by-step explanation:
AB is diameter of a circle means it is a straight line,
so midpoint of straight line with endpoints (X1,Y1),(X2,Y2) is [(X1+X2)/2,(Y1+Y2)/2]
therefore,
(2,-3)=[(X+1)/2,(Y+4)/2],
=> (X+1)/2 = 2,
=> X=3.
& (Y+4)/2 = -3,
=> Y = -10.
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