Question

find the coordinate of a point on x-axis,which is equidistant from the point (-3,4) and (2,5)​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Here is Your Answer:-

Let the required point be ( x,0 )

Since, ( x,0 ) is equidistant from the points ( -3,4 ) and ( 2,5 )

• √( -3 - x )^2 + ( 4 - 0 )^2 = √( 2 - x )^2 + ( 5 - 0 )^2 [ Using Distance Formula ]

⇏sqrt9 + x^2 + 6x + 16 = √4 + x^2 - 4x + 25

⇏10x = 4

⇏x = 4/10

= 2/5

Required Point is ( 2/5,0 )

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