Question

find the coordinate of a point on y-axis which is equidistant from
m(-5,-2) n(3,2).

answer me fast plzzz​

Answer 1

Answer:

Let point P(0, y) on Y- axis be equidistant from M(-5,-2) and N(3,2). The co-ordinates of the point on the Y-axis which is equidistant from M and N are M (0, -2).

Step-by-step explanation:

$Hope \: it \: helps \: u...$

Answer 2

Step-by-step explanation:

AnSwEr

Let the ordinate of the y axis be k since it is unknown and abscissa of x axis is clearly 0 therefore the coordinate of the point will be (0,y)

Since, the points are equidistant

Therefore, by distance formula,

√(-5–0)^2 + (-2-k)^2 = √(0–3)^2 + (k-2)^2

=> 25 + 4 + 4k + k^2 = 9 + k^2 -4k + 4

=> -25 + 9= 8k

=>k = -16/8

=>k = -2

Therefore coordinate of the point on the y-axis is (0,-2).

Hope it helps...