Question

Find the coordinate of a point which lies on the second quadrant at a distance of 3 units from x axis and 2 units from y axis

Answer 1

Answer:

$\red {Required \:point } \green {= (-2,3)}$

Step-by-step explanation:

$In \: Second \: Quadrant ,\: coordinates \\is\: of \: form \: (-x,y)$

$x - coordinate = Distance \: from \: y -axis \\ = 2$

$y - coordinate = Distance \: from \: x -axis \\ = 3$

$Required \: point = ( -2,3)$

Therefore.,

$\red {Required \:point } \green {= (-2,3)}$

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Answer 2

Answer:

(−2,3)

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