Question

Find the coordinate of B such that the straight line 2y-x-16=0 is perpendicular by sector of the line joining point A (-3,4) and B

Answer 1

Answer:

(- 5, 8)

Step-by-step explanation:

Slopes of perpendicular lines are opposite reciprocal.

2y - x - 16 = 0

2y = x + 16

y = (1/2)x + 8 ..... (1)

Slope of ⊥ line is (- 2)

Use point-slope form of equation

y - 4 = - 2(x - (-3))

y = - 2x - 2  ..... (2)  

Let's find coordinate of intercept Line (1) and line (2)

(1/2)x + 8 = - 2x - 2

(5/2)x = - 10 ===> x = - 4 then y = 6

(-4, 6) is midpoint of segment AB

(-3 + x) / 2 = -4 ===> x = - 5

(4 + y) / 2 = 6 ===> y = 8

B (- 5, 8)