Find the coordinate of centroid of a triangle whose vertices are (0,1),(3,2),(2,-1)
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1
x coordinate is 1/3 ×( 0+3+2) = 5/3
y coordinate is 1/3 ×(1+2+(-1)) = 2/3
y coordinate is 1/3 ×(1+2+(-1)) = 2/3
Answered by
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The formula for coordinates of centric of a triangle is
((X1+X2+X3)/3,(Y1+Y2+Y3)/3)
(0+3+2)/3,(1+2-1)/3
=(5/3,2/3)
((X1+X2+X3)/3,(Y1+Y2+Y3)/3)
(0+3+2)/3,(1+2-1)/3
=(5/3,2/3)
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