Question

find the coordinate of point P on the line segment joining A(1,2) and B(6,7) such that AP= 2/5AB

Answer 1

Hope it is helpful..

Answer 2

Answer: Coordinate of point P is $(3,4)$

Step-by-step explanation:

Since we have given that

A(1,2) and B(6,7).

And AP = $\dfrac{2}{5}AB$

So, AP:BP = 2:3

We will find the coordinates of point P.

So, it becomes,

$\dfrac{1\times 3+6\times 2}{2+3},\dfrac{2\times 3+7\times 2}{2+3}\\\\(\dfrac{3+12}{5},\dfrac{6+14}{5})\\\\=(\dfrac{15}{5},\dfrac{20}{5})\\\\=(3,4)$

Hence, coordinate of point P is $(3,4)$