find the coordinate of the point A whose AB is the diameter of the circle whose centre is (2,-3),and B is (1,4)?
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because AB is diameter of circle
so center divided AB equally
use section formula
2=(x+1)/2
x=3
-3=(y+4)/2
y=-10
hence point A (3,-10)
so center divided AB equally
use section formula
2=(x+1)/2
x=3
-3=(y+4)/2
y=-10
hence point A (3,-10)
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