Question

Find the coordinate of the points of trisection of line segment joining the (7, -2)

and (1,5).​

Answer 1

Given :   line segment joining the (7, -2)  and (1,5).​

To Find  : coordinate of the points of  trisection

Solution:

Let  say

P = ( 7 , -2)

Q = (1 , 5)

Points A & B Trisect PQ

such that PQ

A divided in 1 : 2 Ratio   & B divides in 2 : 1

P = ( 7 , -2) , Q = (1 , 5)

A divided in 1 : 2

A  =  ( 1 * 1 + 2 * 7)/(1 + 2)   , ( 1 * 5  + 2 *(-2))/(1 + 2)

A = ( 1 + 14)/3 , ( 5  - 4) / 3

A = 15/3 , 1/3

A = 5 , 1/3

  P = ( 7 , -2) , Q = (1 , 5)

B divided in 2 : 1

B  =  ( 2 * 1 +1 * 7)/(2+ 1)   , (2 * 5  + 1 *(-2))/(2 + 1)

B= ( 2+ 7)/3 , ( 10  - 2) / 3

B = 9/3 , 8/3

B = 3 , 8/3

P = ( 7 , -2)    A = (5 , 1/3)  , B = (3 , 8/3)   ,  Q = (1 , 5)

(5 , 1/3)  , and  (3 , 8/3)   trisect line segment joining the (7, -2)  and (1,5).​

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