Question

Find the coordiNate's of point that divides the line joining points (4,-3)and (8,5) in ratio 3:1 internally ​

Answer 1

Answer:

We are given,

(x1,y1)=(4,−3) & 1(x2,y2)=(8,5)

Let (x,y)coordinates which divides the line joining the point (x1,y1)

and (x2,y2) in ratio m:n=3:1 internally.

So,(x,y)=(m+nmx2+nx1,m+nmy2+ny1)

=(3+13(8)+1(4),3+13(5)+1(−3))

=(428,412)

(x,y)=(7,3)

Answer 2

Step-by-step explanation:

let A = (4,-3) B =(8,5)

Ratio :-- 3:1 let m1 : m2

so coordinates of point are :

x= m1*x2 +m2*x1 / m1+m2

x=3*8 + 1*4 / 3 +1

x=24 +4 / 4

x=28/4

X=7

Y= m1*y2+m2*y1 /m1+m2

Y=3*5 + 1*-3 /1+3

Y=15-3/4

Y=12/4

Y=3

So, coordinates are (7,3)

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