Find the coordinate where the line x + y = 10 will intersect X-axis. *
(a) (3, 10)
(b) (10, 5)
(c) (10, 0)
(d) (0, 10)
Answers
Answer:
Substitute
0
for
y
, and solve for
x
.
5
x
+
0
=
10
5
x
=
10
Divide both sides by
5
.
x
=
10
5
x
=
2
Point A:
(
2
,
0
)
←
x-intercept
Y-intercept: value of
y
when
x
=
0
Substitute
0
for
x
.
5
(
0
)
+
y
=
10
Simplify.
0
+
y
=
10
y
=
10
Point B:
(
0
,
10
)
←
y-intercept
graph{5x+y=10 [-14.24, 14.23, -7.12, 7.12]}
Answer link
Lorenzo D.
Feb 21, 2018
x-axis
A
=
(
2
,
0
)
y-axis
B
=
(
0
,
10
)
;
Explanation:
5
x
+
y
=
10
is the equation of a straight line.
When you want to find the intersection of a straight line with the axis you basically want to know what is the value of
y
when
x
is equal to
0
(y-axis intercection) and what is the value of
x
when
y
is equal to
0
(x-axis intecection).
x-axis:
when
y
=
0
the equation becomes:
5
x
+
0
=
10
⇒
x
=
10
5
⇒
x
=
2
so the first point is
A
=
(
2
,
0
)
y-axis:
when
x
=
0
the equation becomes:
0
+
y
=
10
⇒
y
=
10
so the second point is
B
=
(
0
,
10
)
graph{5x+y=10 [-10, 10, -5, 5]}
Answer link
Jim G.
Feb 21, 2018
A
(
2
,
0
)
and
B
(
0
,
10
)
Explanation:
to find where the line crosses the x and y axes
∙
let x = 0, in the equation for y-intercept
∙
let y = 0, in the equation for x-intercept
x
=
0
⇒
0
+
y
=
10
⇒
y
=
10
←
y-intercept
y
=
0
⇒
5
x
+
0
=
10
⇒
x
=
2
←
x-intercept
crosses x-axis at
A
(
2
,
0
)
and y-axis at
B
(
0
,
10
)
graph{(y+5x-10)((x-2)^2+(y-0)^2-0.04)((x-0)^2+(y-10)^2-0.04)=0 [-20, 20, -10, 10]}
Step-by-step explanation: