Question

Find the coordinates of a point A, where AB is diameter of circle with centre (3,-1) and point B is (2,6)​

Answer 1

Hey mate here is ur answer--

Centre part of circle be O.(3,-1)

This O point acts a mid point of AB coordinate

so,

let the A coordinates be (x1, y1)

x=x1+x2/2(Mid point formula)

3=x1+2

=> x1=1

y=y1+y2

-1=y1+6

=> y1=-7

So, A coordinates will be (1,-7)

A(1,-7) .Hope it's helpful to you!!!!

Answer 2

Answer:

Centre part of circle be O.(3,-1)

This O point acts a mid point of AB coordinate

so,

let the A coordinates be (x1, y1)

x=x1+x2/2(Mid point formula)

3=x1+2

=> x1=1

y=y1+y2

-1=y1+6

=> y1=-7

So, A coordinates will be (1,-7)

Step-by-step explanation: