Find the coordinates of a point A where AB is diameter of a circle whose centre is (2, -3) and B (1, 4).
Class 10, Coordinate geometry
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Given : AB is diameter of a circle whose centre is (2, -3) and B (1, 4).
To find : Coordinate of A
Solution:
AB is Diameter of circle
A = ( x , y)
B = ( 1 , 4)
Center of Circle = (2 , - 3)
Center of circle is mid point of AB
=> 2 = (x + 1)/2 , -3 = (y + 4)/2
=> 4 = x + 1 , -6 = y + 4
=> x = 3 , y = -10
A = ( 3 , -10)
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