Find the coordinates of a point A, where AB is the diameter of circle whose centre is (2, - 3) and B is (1, 4).
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Answered by
9
let coordinates of A be (x,y)
then, (x+1)/2=2 & (y+4)/2=-3
therefore x=3,y=-10
coordinates of A=(3,-10)
then, (x+1)/2=2 & (y+4)/2=-3
therefore x=3,y=-10
coordinates of A=(3,-10)
Answered by
5
Hey mate...
here's the answer....
Let centre of circle be o ,and coordinate of A be x2,y2 , coordinate of B is x1y1 , coordinate of O 4,-11. On putting formula of middle point x= x1+ x2/2,y= y1+y2/2.A = 3,-24....
Hope this helps❤
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