Question

Find the coordinates of a point on the graph of the equation 3x + 2y = 16, whose y-coordinate is 3/4 times its x-coordinate.​

Answer 1

Step-by-step explanation:

It is given

3x+2y=6

We can also write it as

2y=6−3x

y=

2

6−3x

Substituting x=2 in the given equation

y=

2

6−3(2)

So we get

y=

2

6−6

y=0

Substituting X=4 in the given equation

y=

2

6−3(4)

So we get

Y=

2

6−3(4)

So we get

y=

2

6−12

y=

2

−6

By division

y=−3

x: 2 4

y: 0 -3

Now draw a grapg using the points (2,0)(4,3)

Join the points through a line and find the coordinates which cuts y-axis.

From the graph we know that the line joining the two points cut the y-axis at a point P which is above x-axis at 3 units distance

Therefore, the coordinate of the point is P(0,3)