find the coordinates of a point on the parabola ysquare=8x, whose focal distance is 4
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y^2=4ax,...4a=8
a=2.....and a'=4
then, y=(a,+r- a')
thnn y=(2,4)nd(2,-4)
a=2.....and a'=4
then, y=(a,+r- a')
thnn y=(2,4)nd(2,-4)
0411kaushik:
answer is (2,4) and (2,-4) but thanks for your work
ss sry u also give another focal length na
ok fine
mm
nw u see
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