Find the coordinates of a point p, where Pq is a diameter of a circle whose center is (0,6) and q is the point (3,6) ?
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Answer:
p(-3,6)
Step-by-step explanation:
centre point divides diameter into two equal halves ( radius )
so,(0,6) is the mid point
x+3÷2=0
x+3=0
x=-3
similarly,
y+6÷2=6
y+6=12
y=6
therefore p(-3,6)
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