Question

Find the coordinates of a point which divides the line AB, A(1, 3), B(2, -1)
in the ratio 3:2 internally?

Answer 1

Answer:

Let the point be P(x,y)

Let the ratio be m1:m2=3:2

By putting section formula we get:

P(x,y)={(m1x2+m2x1)/m1+m2,(m1y2+m2y1)/m1+m2}

= {(3*2+2*1)/3+2,(3*(-1)+2*3)/3+2}

= (6+2/5,-3+6/5)

= (8/5,3/5)

Therefore,the coordinates of P(x,y)=(8/5,3/5)