Question

Find the coordinates of a point which is at a distance of 10 units from (0,1) and at a distance of 5 units from (3,5)​

Answer 1

Answer:

(6,9)

Step-by-step explanation:

Let coordinates be (x,y)

Now Distance between (x,y) & (0,1)= sqrt[x^2+(y-1)^2]

But it is equal to 10. So sqrt[x^2+(y-1)^2]=10=> x^2+(y-1)^2=100....EQ1

Now distance between point (x,y) & (3,5) = sqrt[(x-3)^2+(y-5)^2]

But it is equal to 5. So sqrt[(x-3)^2+(y-5)^2]=5=>(x-3)^2+(y-5)^2=25....EQ2

From EQ1 and EQ2, x=6 y=9