Question

Find the coordinates of a point whose distance from the point (3,5) is 5 units and from the point
(0,1) is 10 units.​

Answer 1

Answer:

Step-by-step explanation:

(x-3)^2+(y-5)^2=25

x^2+9-6x+y^2+25-10y=25

x^2+y^2-6x-10y+9=0 be eq 1

(x-0)^2+(y-1)^2=10

x^2+y^2+1-2y=10 be eq 2

From eq 1 and eq2

6x+10y=9 be eq3

2y= -9

y=-9/2

Substitute eq3

We get x=49/2