Math, asked by tanuagrawal1234567, 1 year ago

find the coordinates of a point whose distance from the point (3,5) is 5 units and that from the point (0,1) is 10 units

Answers

Answered by ria113
24
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Answered by wifilethbridge
7

Answer:

( 2,\frac{11}{3})

Step-by-step explanation:

Refer the attached figure

P=(3,5)

Let Q be (x,y)

R = (0,1)

m:n =5:10

Using Section Formula : x=\frac{mx_2+nx_1}{m+n}  , y=\frac{my_2+ny_1}{m+n}

So,P=(x_1,y_1)=(3,5)

R=(x_2,y_2)=(0,1)

Substitute the values in the formula :

x=\frac{5(0)+10(3)}{5+10}  , y=\frac{5(1)+10(5)}{10+5}

x=\frac{30}{15}  , y=\frac{55}{15}

x=2  , y=\frac{11}{3}

Hence the coordinates of a point whose distance from the point (3,5) is 5 units and that from the point (0,1) is 10 units is ( 2,\frac{11}{3})

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