Question

Find the coordinates of ABCD if area of square is 25 square units, and A is on origin and AB is on positive x axis.

Please Answer it correctly​

Answer 1

Answer:

Given: Coordinates of Point A(1,3),B(−1,0) and C(4,0)

Construction: Drop a perpendicular from A on x− axis, which meets x-axis at D≡(1,0)

Now in ΔADC,AD=3,DC=3

Area of ΔADC=21×DC×AD

=21×3×3=29 cm2

Now in ΔADB,AD=3,DB=2

Area of ΔADB=21×DB×AD

=21×2×3=3 cm2

Area of ΔABC= Ara of ΔADC+ Area of ΔABD

=29+3=215=7.5 cm2

Answer 2

Answer:

Step-by-step explanation:

(i) Distance of A from the Y-axis = OL = -6 units

Distance of A from the X-axis = AL = 5 units

Hence, the coordinates of A are (-6,5).

(ii) Distance of B from the Y-axis = OM = 5 units

Distance of B from the X-axis = BM = 4 units

Hence, the coordinates of B are (5,4).

(iii) Distance of C from the Y-axis = ON = -3 units

   Distance of C from the X-axis = CN = 2 units

   Hence, the coordinates of C are (-3,2).

(iv) Distance of D from the Y-axis = OP = 2 units

  Distance of D from the X-axis = DP = -2 units

   Hence, the coordinates of D are (2,-2).

(v) Distance of E from the Y-axis = OL = -1 units

    Distance of E from the X-axis = AL = -4 units

    Hence, the coordinates of E are (-1,-4).