Question

Find the coordinates of circumcentre of circle whose
vertices are (6,-6), (3, -7) and (3, 3):​

Answer 1

Answer:

Let A (6,-6), B (3,-7) and C (3,3) be the vertices of the triangle and P (x,y)be the circumcentre. Then

pa = pb =pc

pa^2 = pb^2 =pc^2

(x-6)^2 + (y--6)^2 = (x-3)^2 + (y+7)^2

after simplification

3x+y=7....(1)

pb^2=pc^2

(x-3)^2 +(y+7)^2 = (x-3)^2+(y-3)^2

after simplification

y +2=0

y=-2

putting this value of y in (1) you get x =3

Ans 3,-2