Find the coordinates of P which divides the line segment joining A(3, 7) and B(9, 4), such that
5AP = 4PB.
Answers
Answered by
0
Answer:
We know that by section formula, the co-ordinates of the points which divide internally the line segment joining the points (x
1
,y
1
) and (x
2
,y
2
) in the ratio m:n is
(x,y)=(
m+n
mx
2
+nx
1
,
m+n
my
2
+ny
1
)
The end points of AB are A(4,-3) and B(9,7).
Therefore,
(x
1
=4,y
1
=−3) and (x
2
=9,y
2
=7)
Also, m=3 and n=2
Let the required point be P(x,y).
Using section formula,
x=
m+n
mx
2
+nx
1
,y=
m+n
my
2
+ny
1
x=
5
3×9+2×4
=7,y=
5
3×7+×−3
=3
Therefore, the required point is P(7,3).
Step-by-step explanation:
Answered by
1
Step-by-step explanation:
- ratio = 4:5
- coordinates = A(3,7),B(9,4)
- taking formula = m1×x2+m2×x1/m1+m2
- x = 9*4+5*3/4+5=51/9 = 17/3 ans
- y= 5*7+4×4/4+5 = 51/9 =17 / 3 ans
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