Find the coordinates of point a where ab is diameterof circle whosr centre is (2,-3)&b(1,4)
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Answer:
A(3,-10)
Step-by-step explanation:
A(x,y)
B(1,4)
C(2,-3)
m:n = 1:1 ( C is the mid point )
BY MID POINT FORMULA
C(2,-3) = C(1+x / 2 , 4+y / 2)
Now,
2 = 1+x / 2
2*2 = 1+x
4 = 1+x
x = 4-1
x = 3
Similarly,
-3 = 4+y / 2
-3*2 = 4+y
-6 = 4+y
y = -4-6
y = -10
Therefore,
x = 3
y = -10
Hence, the coordinates of point A(x,y) = A(3,-10)
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# jasleenlehri13......
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