Question

find the coordinates of points c and d.​

Answer 1

Answer:

∆ABC is a equilateral triangle

AC = BC = AB

BC = 2a

in right angle triangle COB,

${BC }^{2} = CO^{2} +OB ^{2}$

$( {2a})^{2} = a ^{2} + CO^{2}$

$4 {a}^{2} = {a}^{2} +CO ^{2}$

${4a}^{2} - {a}^{2} = CO^{2}$

${CO}^{2} = 3 {a}^{2}$

$CO = \sqrt{3 {a}^{2} }$

$c = (0,\sqrt{3a} )$

$similarly \:D \: = (0, \sqrt{3a} )$

Answer 2

Answer:

Hey frnd!!

Here is ur answer❤

∆ABC is an equilateral triangle.

so, AB=BC=AB

BC=2a ........... (i)

Now, in right angled ∆COB,

BC²=CO²+OB²

(2a) ²=a²+CO²

4a²-a²=CO²

CO²=3a²

CO=√3a²

C=(0, √3a)

Similarly, D=(0, √3a)

Hope it helps

#shruti