Question

Find the coordinates of points on x-axis which are at a distance of 5 units from the points (5,-4)​

Answer 1

Answer:

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Step-by-step explanation:

Using distance formula for distance between (5,-4) and (x, 0)

25 = (5-x)^2 + (-4-0)^2

25 = (5-x)^2 + 16

(5-x)^2 = 9

Taking sq. root on both sides,

5-x = 3, 5-x = - 3

x = 2,8

therefore the required points are (2,0) and (8,0)