find the coordinates of points on y axis which is nearest the - 2 and 5
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let the point b (h, 0)
distance =√[(h+2)^2 + 25]
this distance has to min.. min value of perfect squares =0
"therefore distance! =√0+25=5
at h+2=0
h=-2
THERFORE, Pt is (-2,0)
distance =√[(h+2)^2 + 25]
this distance has to min.. min value of perfect squares =0
"therefore distance! =√0+25=5
at h+2=0
h=-2
THERFORE, Pt is (-2,0)
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