Question

find the coordinates of r if it divides they jone of p=3,2 q=6,-1 in the ratio of 1:2​

Answer 1

Given:

☛ Point P(x1,y1) = (3,2)

☛ Point Q(x2, y2) = (6,-1)

☛ Point R divides the line segment PQ in the ratio 1 : 2

To Find:

☛ Coordinates of point R

Solution:

☛ Ratio = 1 : 2

On comparing,

➜ m = 1 , n = 2

By Section formula,

☛ Abscissa of Point R = mx2 + nx1 / m + n

➜ 1(6) + 2(3) / 1 + 2

➜ 6 + 6 / 3

➜ 12/3

➜ 4

Also,

☛ Ordinate of Point R = my2 + ny1 / m + n

➜ 1(-1) + 2(2) / 1 + 2

➜ -1 + 4 / 3

➜ 3/3

➜ 1

Hence, Coordinates of R is (4,1)

Answer 2

by using section formula

(m1x2+m2x1/m1+m2),(m1y2+m2y1/m1+m2)

(1(6)+2(3)/1+2), (1(-1)+2(2)/1+2)

(6+6/3 , -1+4/3)

(12/3 , 3/3)

(4,1)

is the required point