Find the coordinates of the centre of the circle passing through the
points P(6,-6), Q(3,-7)and R(3,3).
Answers
Answered by
36
Answer:
Let the center of the circle be A(x,y)
Then PA=PQ
PA 2=QA 2
(x−6) 2 +(y+6) 2 =(x−3) 2 +(y+7) 2
3x+y−7=0 --- (i)
AP=AR
(AP) 2 =(AR) 2
(x−6)
2 +(y+6)
2 =(x−3) 2 +(y−3) 2 3x−9y−27=0 ---- (ii) (ii) - (i),
we get y=−2
put in (i)x=3
Therefore center of the circle is (3,−2)
Answered by
1
Answer:
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