Question

find the coordinates of the centre of the circle passing through the point p in (6 - 62 in) 3 - 7 and are in bracket 3 ,3

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Answer 1

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Let the center of the circle be A(x,y)

Then PA=PQ

PA2=QA2

(x−6)2+(y+6)2=(x−3)2+(y+7)2

3x+y−7=0  --- (i)

AP=AR

(AP)2=(AR)2

(x−6)2+(y+6)2=(x−3)2+(y−3)2

3x−9y−27=0  ---- (ii)

(ii) - (i), we get 

y=−2

put in (i)

x=3

Therefore center of the circle is (3,−2)