Math, asked by adityak4m6le007, 1 month ago

Find the coordinates of the foci and the vertices, the

eccentricity and the length of the latus rectum of the hyperbolas.
5 {y}^{2}  - 9 {x}^{2}  = 36

Answers

Answered by vivekdek
0

Answer:

The given equation is 5y

2

−9x

2

=36

(

5

36

)

y

2

4

x

2

=1

(

5

6

)

2

y

2

2

2

x

2

=1...(1)

On comparing equation (1) with the standard equation of hyperbola

i.e.,

a

2

y

2

b

2

x

2

=1,

we obtain a=

5

6

and b=2

We know that a

2

+b

2

=c

2

, where c=ae

∴c

2

=

5

36

+4=

5

56

⇒c=

5

56

=

5

2

14

Therefore, the coordinates of the foci are (0,±

5

2

14

)

The coordinates of the vertices are (0,±

5

6

)

Eccentricity e=

a

c

=

(

5

6

)

(

5

2

14

)

=

3

14

Length of latus rectum =

a

2b

2

=

(

5

6

)

2×4

=

3

4

5

Answered by Anonymous
4

Answer:

The given equation is 5y

2

−9x

2

=36

(

5

36

)

y

2

4

x

2

=1

(

5

6

)

2

y

2

2

2

x

2

=1...(1)

On comparing equation (1) with the standard equation of hyperbola

i.e.,

a

2

y

2

b

2

x

2

=1,

we obtain a=

5

6

and b=2

We know that a

2

+b

2

=c

2

, where c=ae

∴c

2

=

5

36

+4=

5

56

⇒c=

5

56

=

5

2

14

Therefore, the coordinates of the foci are (0,±

5

2

14

)

The coordinates of the vertices are (0,±

5

6

)

Eccentricity e=

a

c

=

(

5

6

)

(

5

2

14

)

=

3

14

Length of latus rectum =

a

2b

2

=

(

5

6

)

2×4

=

3

4

5

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