Question

Find the coordinates of the foci, the vertices , length of major axis and minor axis ,eccentricity and latus rectum of the ellipse 2 100 + 2 400= 1​

Answer 1

Answer:

The given equation is 100x2+400y2=1 or 102x2+202y2=1

The given equation is 100x2+400y2=1 or 102x2+202y2=1Here the denominator of 400y2 is greater than the denominator of 100x2

The given equation is 100x2+400y2=1 or 102x2+202y2=1Here the denominator of 400y2 is greater than the denominator of 100x2Therefore, the major axis is alon the y-axis while the minor axis is along the x-axis.

The given equation is 100x2+400y2=1 or 102x2+202y2=1Here the denominator of 400y2 is greater than the denominator of 100x2Therefore, the major axis is alon the y-axis while the minor axis is along the x-axis.On comparaing, the given equation with b2x2+a2y2=1 we obtain b=10 and a=20

The given equation is 100x2+400y2=1 or 102x2+202y2=1Here the denominator of 400y2 is greater than the denominator of 100x2Therefore, the major axis is alon the y-axis while the minor axis is along the x-axis.On comparaing, the given equation with b2x2+a2y2=1 we obtain b=10 and a=20∴ae=c=a2−b2=400−100=300=103

The given equation is 100x2+400y2=1 or 102x2+202y2=1Here the denominator of 400y2 is greater than the denominator of 100x2Therefore, the major axis is alon the y-axis while the minor axis is along the x-axis.On comparaing, the given equation with b2x2+a2y2=1 we obtain b=10 and a=20∴ae=c=a2−b2=400−100=300=103The coordinates of the foci are (0,±103)

The given equation is 100x2+400y2=1 or 102x2+202y2=1Here the denominator of 400y2 is greater than the denominator of 100x2Therefore, the major axis is alon the y-axis while the minor axis is along the x-axis.On comparaing, the given equation with b2x2+a2y2=1 we obtain b=10 and a=20∴ae=c=a2−b2=400−100=300=103The coordinates of the foci are (0,±103)The coordinates of the vertices bare (0,±20)

are (0,±20)Length of major axis =

Step-by-step explanation:

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