Find the coordinates of the foci, the vertices, the length of
major axis, the minor axis, the eccentricity and the length
of the latus rectum of the ellipse. x^2/16+y^2/9=1
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Answer:
Given :
Equation of ellipse :
x² / 16 + y² / 9 = 1
= > x² / 4² + y² / 3² = 1
We have standard equation of ellipse :
i.e. x² / a² + y² / b² = 1
On comparing we get :
a = 4 and b = 3
We know :
a² = b² + c²
c = √ ( a² - b² )
c = √ 7
Now coordinate of foci ( ± c , 0)
= > c ( ± √ 7 , 0 )
Vertices ( ± a , 0 )
= > ( ± 4 , 0 )
Length of major axis = 2 a
= > 8
Length of minor axis = 2 b
= > 6
Eccentricity e = c / a
e = √ 7 / 4
Length of lotus rectum = 2 b² / a
= > 2 × 9 / 4
= > 9 / 2 .
Hence we get answer.
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