Find the coordinates of the focus,axis of the parabola, the equation of the directrix and the length of the latusrectum
Y^2 = 10x.
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Answer:
The given equation is y
2
=10x
Here the coefficient of x is positive.
Hence the parabola opens towards the right
On comparing this equation with y
2
=4ax , we get
4a=10
⇒a=
2
5
∴ Coordinates of the focus =(a,0)=(
2
5
,0)
Axis of the parabola is the x-axis i.e y=0
Equation of directrix x=−a i.e.x=−
2
5
Length of latus rectum =4a=10
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