find the coordinates of the foot of prependicular drawn from the point (3,4) on the line x+y-2=0
Answers
GIVEN.
foot of perpendicular drawn from the point
=> ( 3,4) on the line x + y - 2 = 0
EXPLANATION.
equation of line = x + y - 2 = 0
equation of the curve = y = mx + c
=> y = 2 - x
=> y = -x + 2
slope of the line = -1
=> point are = ( 3,4)
Let we assume that ( a, b) are coordinate of
foot of perpendicular.
then equation will be written as = a + b - 2 = 0
as we know that,
=> M1 X M2 = -1
=> -1 X M2 = -1
=> M2 = 1
equation of perpendicular
=> ( y - Y1) = m ( x - X1)
=> ( b - 4 ) = 1 ( a - 3 )
=> b - 4 = a - 3
=> b - a = 1 .....(2)
From equation (1) and (2) we get,
=> a + b = 2 .....(1)
=> b - a = 1 .....(2)
we get,
=> 2b = 3
=> b = 3/2
put the value of b = 3/2 in equation (1)
we get,
=> a + 3/2 = 2
=> a = 2 - 3/2
=> a = 4 - 3 / 2
=> a = 1/2
Therefore,
The coordinate of foot of perpendicular
drawn from the point ( 3,4)
=> ( 1/2 , 3/2 )
find the coordinates of the foot of prependicular drawn from the point (3,4) on the line x+y-2=0
Tʜᴇ ғᴏᴏᴛ ᴏғ ᴘᴇʀᴍᴇɴᴅɪᴄᴜʟᴀʀ ᴅʀᴀᴡɴ ғʀᴏᴍ ᴛʜᴇ ᴘᴏɪɴᴛ
➪ (3,4) ɪɴ ᴛʜᴇ ʟɪɴᴇ x + ʏ - 2 = 0
ᴇǫᴜᴀᴛɪᴏɴ ᴏғ ʟɪɴᴇ = x + ʏ - 2 = 0
ᴇǫᴜᴀᴛɪᴏɴ ᴏғ ᴛʜᴇ ᴄᴜʀᴠᴇ = ʏ = ᴍx + ᴄ
→ ʏ = 2 - x
→ ʏ = -x + 2
Sʟᴏᴘᴇ ᴏғ ᴛʜᴇ ʟɪɴᴇ = -1
→ ᴘᴏɪɴᴛs ᴀʀᴇ = (3,4)
ɴᴏᴡ, ʟᴇᴛ ᴜs ᴀssᴜᴍᴇ ᴛʜᴀᴛ (ᴀ,ʙ) ᴀʀᴇ ᴄᴏᴏʀᴅɪɴᴀᴛᴇ ᴏғ ғᴏᴏᴛ ᴏғ ᴘᴇʀᴘᴇɴᴅɪᴄᴜʟᴀʀ.
ᴛʜᴇɴ, ᴇǫ ᴡɪʟʟ ʙᴇ ᴡʀɪᴛᴛᴇɴ ᴀs ᴀ + ʙ - 2 = 0
ᴀs ᴡᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ,
→ ᴍ1 × ᴍ2 = -1
→ ᴍ2 = 1
Eǫᴜᴀᴛɪᴏɴ ᴏғ ᴘᴇʀᴘᴇɴᴅɪᴄᴜʟᴀʀ,
→ (ʏ-ʏ1) = ᴍ(x-x1)
→ ʙ - 4 = 1 ( ᴀ-3)
→ ʙ - 4 = ( ᴀ-3)
→ ʙ - ᴀ = 1........................................................(2)
ғʀᴏᴍ ᴇǫ 1 ᴀɴᴅ 2, ᴡᴇ ɢᴇᴛ,
→ ᴀ + ʙ = 2....................................(1)
→ ʙ - ᴀ = 1......................................(2)
ғʀᴏᴍ ᴀʙᴏᴠᴇ ᴡᴇ ɢᴇᴛ,
→ 2ʙ = 3
→ ʙ =
Pᴜᴛᴛɪɴɢ ᴛʜᴇ ᴠᴀʟᴜᴇ ᴏғ ʙ = ɪɴ ᴇǫ (1) ᴡᴇ ɢᴇᴛ,
→ᴀ + = 2
→ᴀ = 2 -
→ᴀ = 4 -
→ᴀ =
ᴛʜᴇʀᴇғᴏʀᴇ, ᴛʜᴇ ᴄᴏᴏʀᴅɪɴᴀᴛᴇ ᴏғ ᴛʜᴇ ғᴏᴏᴛ ᴏғ ᴘᴇʀᴘᴇɴᴅɪᴄᴜʟᴀʀ ᴅʀᴀᴡɴ ғʀᴏɴ ᴛʜᴇ ᴘᴏɪɴᴛ (3,4)
ᴛʜᴇ ᴛᴡᴏ ᴘᴏɪɴᴛs ᴀʀᴇ ᴀɴᴅ .