find the coordinates of the mid point (8,9) and (2,-9)
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Answered by
0
Answer:
(8,9) - first quadrant
(2,-9) - fourth quadrant
Answered by
2
Answer:
(x2,y2) = √(x2-x1) ²+(y2-y1) ²
= √ (x-8)²+ (y-9) ²------------------------------------------1
and (x2,y2) = √(x3-x2) ²+(y3-y2) ²
= √(2-x) ²+(-9-y) ²--------------------------2
from 1 nd 2 we get,
√(x-8)²+(y-9)²= √(2-x)²+(-9-y)²
squaring both sides
(x-8) ²+(y-9) ² = (2-x)²+(-9-y)²
solve it further to get your answer...
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