Question

Find the coordinates of the piont on x-axis which is equisdistant from the piont (-2,5) &(2,-3)​

Answer 1

Answer:

let the coordinates A(x,0)

Using distance formula,

√(x+2)^2+(-5)^2=√(x-2)^2+(3)^2

or, x^2+4x+29=x^2-4x+13

or,x=-16/8=-2

So,A(-2,0) is the required coordinate

Answer 2

Answer:

thanks

Step-by-step explanation: