Question

Find the coordinates of the point equidistant from three given points A(5, 3), B(5, –5) and C(1, –5)

Answer 1

Answer:

mid point of BC (5+1)/2 = 3 and (-5 -5)/2 = -5

R = (3, -5)

The point equi distant from A, B and C is centroid of triangle ABC

Let this point be P

then AP: PR = 2:1

coordinate of A (5,3) and R (3, -5)

You can apply the section formula now to get the coordinates of P