Question

Find the coordinates of the point in y-axis which is nearest to the point (-2, 5)

Answer 1

Let A ( -2,5)

Since , the required point is in y-axis it's x- co-ordinates will be 0.

Let required point = B ( 0,a)
we need to find coordinates of point,
such that Distance AB is minimum

Finding AB,
x= -2 , y = 5
x^2= 0 , y^2 = a( uprooted)

AB= √(x-x^1)^2+(y^2- y^1) ^2

√ {0-(-2)}^2+ (a-5)^2

√ (2)^2+ ( a- 5)^2

√(6)^2+ (a-5)^2

Now, AB is least when a-5 =0
a= 5

so, coordinates of required point= (0,5)


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