Question

find the coordinates of the point of trisection of the line segment joining the points A ( 2, - 2 )and b (- 7+4)​

Answer 1

The points of trisection of the line segment AB are (-1,0) and (-4,2).

Step-by-step explanation:

It is given that the end points of line segment AB are A ( 2,-2 )and B(-7,4)​.

Section formula:

$(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n})$

Points of trisection divides a line segment in three equal parts.

First point of trisection divides AB in 1:2.

First point = $(\dfrac{(1)(-7)+(2)(2)}{1+2},\dfrac{(1)(4)+(2)(-2)}{1+2})$

                = $(\dfrac{-3}{3},\dfrac{0}{3})$

                = $(-1,0)$

Second point of trisection divides AB in 2:1.

Second point = $(\dfrac{(2)(-7)+(1)(2)}{2+1},\dfrac{(2)(4)+(1)(-2)}{2+1})$

                = $(\dfrac{-12}{3},\dfrac{6}{3})$

                = $(-4,2)$

Therefore, the points of trisection of the line segment AB are (-1,0) and (-4,2).

#Learn more

Find the coordinates of the point which divides (3,2) and (2,3) in the ratio 1:2 ????​

https://brainly.in/question/13141849