Question

find the coordinates of the point on the curve y=6x-x^2 the tangent at which is parallel to the line y=-4x​

Answer 1

Step-by-step explanation:

y=6x−x

2⇒y

′

=6−2x as tangent is parallel to line4x−2y−1=0 slope =2

⇒6−2x=2

⇒x=2

So y=6⋅2−2

2=8

Hence the point of tangency is (2,8)

please mark me brilliant

Answer 2

coordinates are (5,5) .... slopes are 6-2x and -4