Question

Find the coordinates of the point on x-axis equidistant from the points (2,5)and (3,4)​

Answer 1

Answer:

(-2,0)

Step-by-step explanation:

Let P be the point on the x-axis

and AP= BP(given)

√(x2-x1)²+ (y2-y1)²= √(x2-x1)²+ (y2-y1)²                   (Distance formula)

√(2-x)²+ (5-0)²= √(3-x)²+ (4-0)²                                 (y=0)

4- 4x+ x²+ 25= 9- 6x+ x²+ 16                                      (sqrt get cancels)

- 4x+ 29= -6x+ 25                                                       (x² gets cancelled)

-4x+ 6x= 25- 29

2x= -4

x= -2

∴The point is (-2, 0)

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