Question

find the coordinates of the point on x-axis which are at a distance of 5 units from the point (5,4)

Answer 1

Using distance formula for distance between (5,4) and (x, 0)
25 = (5-x)^2 + (4-0)^2
25 = (5-x)^2 + 16
(5-x)^2 = 9
Taking sq. root on both sides,
5-x = 3, 5-x = - 3
x = 2,8

therefore the required points are (2,0) and (8,0)

Answer 2

Answer:

Using distance formula for distance between (5,4) and (x, 0)

25 (5-x)^2+(4-0)^2 25=(5-x)^2 + 16

(5-x)^2 = 9

Taking sq. root on both sides,

5-x3,5-x-3

x = 2,8

therefore the required points are (2,0) and (8,0)