Question

find the coordinates of the point on y-axis which is nearest to the point (-2,5).

Answer 1

Let the point on the y axis which is closest to the point P(-2, 5) be Q(0, b).

Equation of y axis :  x = 0.

The perpendicular distance of P(-2, 5) from y axis :  | -2 | /√1 = 2.

So    PQ = 2
        PQ² = 2²
        (-2+0)² + (5 - b)² = 2²
       =>  b = 5.
 
So the nearest point on y axis :   (0, 5).

Answer 2

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